Penyajian data dalam bentuk tabel frekuensi:
1.Menentukan rentangan nilai (r) = nilai tertinggi – nilai terendah
2.Menentukan banyak kelas interval
(k) = 1 + 3,3 log n
3.Panjang kelas interval
(p) = r/k
Keterangan:
n = banyak data
yang digunakan
misal:
hasil uji coba instrumen dubuat dalam bentuk:
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No
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Nama Siswa
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Butir Soal
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Skor
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1
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2
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3
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4
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5
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6
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7
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8
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9
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10
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11
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12
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13
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14
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15
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16
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17
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18
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19
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20
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total
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||
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1
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YOHANES ANTONIUS SAE
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1
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1
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1
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1
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0
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0
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1
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1
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1
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1
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0
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1
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0
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0
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1
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1
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1
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1
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1
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1
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15
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2
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3
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4
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5
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No
|
Nilai
|
No
|
Nilai
|
|
Responden
|
Siswa
|
Responden
|
Siswa
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|
1
|
7.5
|
17
|
8.0
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2
|
8.0
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18
|
5.5
|
|
3
|
6.5
|
19
|
8.0
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|
4
|
7.0
|
20
|
6.5
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|
5
|
6.0
|
21
|
6.0
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|
6
|
6.0
|
22
|
5.5
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|
7
|
7.0
|
23
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6.0
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|
8
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6.0
|
24
|
7.5
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|
9
|
5.0
|
25
|
8.0
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|
10
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7.0
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26
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6.5
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|
11
|
8.0
|
27
|
5.5
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|
12
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6.0
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28
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5.5
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|
13
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8.0
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29
|
5.5
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|
14
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7.0
|
30
|
7.0
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|
15
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8.5
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31
|
6.5
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|
16
|
7.0
|
32
|
7.5
|
maka
Rentang = Nilai tertinggi - nilai terendah
= 8,5 - 5,0 = 3,5
Banyaknya Kelas = 1 +
(3,3 log 32) = 5,9
P = rentang / banyaknya kelas
= 3,5 /
5,9 = 0,6
distribusi nilai siswa:
|
Rentang
|
Jumlah
|
|
Nilai
|
Siswa
|
|
5,0 - 5,6
|
6
|
|
5,7 - 6,3
|
6
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6,4 - 7,0
|
10
|
|
7,1 - 7,7
|
3
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|
7,8 - 8,4
|
6
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8,5 - 9,1
|
1
|
